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Tag: GATE MT 2017 Question Paper with Solution

Get all set of GATE MT (Metallurgy) question papers with solution. Download the pdf of GATE MT 2017 previous year question papers with solution.

Askmemetallurgy Official

Asked: July 6, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q47.

W-Ni compact is prepared by liquid phase sintering is 1500°C. If the size of the tungsten grains is 40µm and the interfacial tungsten- tungsten and tungsten-nickel energies are 0.52 and 0.30 Jm-2 respectively, the predicted average neck size (in µm) ...Read more

W-Ni compact is prepared by liquid phase sintering is 1500°C. If the size of the tungsten grains is 40µm and the interfacial tungsten- tungsten and tungsten-nickel energies are 0.52 and 0.30 Jm^-2 respectively, the predicted average neck size (in µm) of sintered tungsten grain is:

(Melting points of tungsten and nickel are 3410°C and 1453°C, respectively)

(A) 10 (B) 15 (C) 20 (D) 25

Askmemetallurgy Official

Asked: July 6, 2020In: Metal Working (Forming)

GATE MT 2017 Q46.

A 250mm thick slab of nickel alloy is subjected to cold rolling using a roll of diameter 450mm. If the angle of bite during rolling is 10°, the maximum possible reduction (in mm) during rolling is ____ (answer up to ...Read more

A 250mm thick slab of nickel alloy is subjected to cold rolling using a roll of diameter 450mm. If the angle of bite during rolling is 10°, the maximum possible reduction (in mm) during rolling is ____ (answer up to two decimal places)

Askmemetallurgy Official

Asked: July 5, 2020In: Foundry Technology (Metal Casting)

GATE MT 2017 Q45.

Total time for solidification of a cubic casting of dimensions 5.0 cm×5.0 cm ×5.0cm is 1.6 min. A cylindrical riser with diameter to height ratio 0.5 is required so that the time for solidification of riser is 3.2 min. Applying ...Read more

Total time for solidification of a cubic casting of dimensions 5.0 cm×5.0 cm ×5.0cm is 1.6 min. A cylindrical riser with diameter to height ratio 0.5 is required so that the time for solidification of riser is 3.2 min. Applying Chvorinov’s law, the height of the riser (in cm) is _____ (answer up to two decimal places)

(Assume that exponent (n) in Chvorinov’s equation is 2)

Askmemetallurgy Official

Asked: July 5, 2020In: Mechanical Metallurgy

GATE MT 2017 Q44.

A perfectly elastic-plastic material has a yield stress of 450 MPa and fractures at a strain 0f 0.45. The ratio of resilience to toughness for this material is _____ (answer up to three decimal places) Given the young’s modulus E=4.5 GPa

A perfectly elastic-plastic material has a yield stress of 450 MPa and fractures at a strain 0f 0.45. The ratio of resilience to toughness for this material is _____ (answer up to three decimal places)

Given the young’s modulus E=4.5 GPa

Askmemetallurgy Official

Asked: July 5, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q43. A single crystal of a FCC metal is subjected to a sufficiently large tensile stress along the [110] direction to activate some of the slip systems. Which one of the following slip systems will be activated:

Poll Results

33.33%(A) a/2[1-10][111] ( 21 voters )

46.03%(B) a/2[011][111-] ( 29 voters )

12.7%(C) a/2[011][11-1] ( 8 voters )

7.94%(D) a/2 [110][1-11-] ( 5 voters )

Based On 63 Votes

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Askmemetallurgy Official

Asked: July 5, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q41.

During heat treatment of a cold worked metal, recrystallization is 20% complete after 100s. The transformation (in %) in 400s is _____(answer up to two decimal places) (Assume Avrami constant, n=2)

During heat treatment of a cold worked metal, recrystallization is 20% complete after 100s. The transformation (in %) in 400s is _____(answer up to two decimal places)

(Assume Avrami constant, n=2)

Askmemetallurgy Official

Asked: July 5, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q42. At low temperatures, two parallel edge dislocations lying on parallel planes are shown in different configurations below.

Poll Results

41.46%(A) P-3,Q-2,R-4,S-1 ( 17 voters )

12.2%(B) P-4,R-1,R-3,S-2 ( 5 voters )

24.39%(C) P-1,Q-3,R-2,S-4 ( 10 voters )

21.95%(D) P-2,Q-4,R-1,S-3 ( 9 voters )

Based On 41 Votes

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GATE MT 2017 Q42. At low temperatures, two parallel edge dislocations lying on parallel planes are shown in different configurations below.

Askmemetallurgy Official

Asked: July 4, 2020In: Mechanical Metallurgy

GATE MT 2017 Q40.

A steel component is subjected to fatigue loading : σ(maximum)= 200 MPa, σ(minimum)=0. The component has an initial crack length of 1mm. Propagation of crack is governed by: da/dN= 10-12 (ΔK)3, where, the crack length a is in metres, N ...Read more

A steel component is subjected to fatigue loading : σ(maximum)= 200 MPa, σ(minimum)=0. The component has an initial crack length of 1mm. Propagation of crack is governed by: da/dN= 10^-12(ΔK)³, where, the crack length a is in metres, N is the number of cycles and ΔK is in MPa m^1/3. The crack length of (in m) after one million cycles will be _____ (answer up to three decimal places)

Askmemetallurgy Official

Asked: July 4, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q39.

For an intrinsic semiconductor, the room temperature electrical conductivity is 10-6 Ω-1m-1. If the electron and hole mobilities are 0.75 and 0.06 m2V-1s-1 respectively, the intrinsic carrier concentration (per m3) at room temperature is: (A) 1 × 1012 (B) 7 ×1012 ...Read more

For an intrinsic semiconductor, the room temperature electrical conductivity is 10^-6 Ω^-1m^-1. If the electron and hole mobilities are 0.75 and 0.06 m²V^-1s^-1respectively, the intrinsic carrier concentration (per m³) at room temperature is:

(A) 1 × 10¹²(B) 7 ×10¹²(C) 3 ×10¹² (D) 1.1 ×10¹⁴

Askmemetallurgy Official

Asked: July 4, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q38. Arrange the magnetic moment of neighbouring atoms in a one-dimensional lattice in Group 1 to the corresponding magnetic material in Group 2.

Poll Results

9.38%(A) P-4,Q-1,R-3,S-2 ( 3 voters )

71.88%(B) P-3,Q-4,R-1,S-2 ( 23 voters )

9.38%(C) P-2,Q-4,R-1,S-3 ( 3 voters )

9.38%(D) P-1,Q-2,R-3,S-4 ( 3 voters )

Based On 32 Votes

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GATE MT 2017 Q38. Arrange the magnetic moment of neighbouring atoms in a one-dimensional lattice in Group 1 to the corresponding magnetic material in Group 2.

Askmemetallurgy Official

Asked: July 4, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q37.

Assuming the solid phases to be pure, the slope of line BC in the predominance area diagram schematically shown below is _____ (answer up to two decimal places) Read more

Assuming the solid phases to be pure, the slope of line BC in the predominance area diagram schematically shown below is _____ (answer up to two decimal places)

2017 44

Askmemetallurgy Official

Asked: July 4, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q36.

For homogenous nucleation of solid in liquid of a pure metal, the critical edge length (in nm) of a cube shaped nucleus is ______. (answer up to two decimal places) Given surface energy γ=0.177 Jm-2 ; change in volume free energy ...Read more

For homogenous nucleation of solid in liquid of a pure metal, the critical edge length (in nm) of a cube shaped nucleus is ______. (answer up to two decimal places)

Given surface energy γ=0.177 Jm^-2; change in volume free energy ΔG_v = -2.8 × 10⁸ Jm^-3)

Askmemetallurgy Official

Asked: July 3, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q35.

Pure orthorhombic sulphur transforms to stable monoclinic sulphur above 368.5 K. Applying the third law of thermodynamics, the value of entropy (in JK-1) of transformation at 368.5 K is _____ (answer up to two decimal places) Given: Entropy change associated with ...Read more

Pure orthorhombic sulphur transforms to stable monoclinic sulphur above 368.5 K. Applying the third law of thermodynamics, the value of entropy (in JK^-1) of transformation at 368.5 K is _____ (answer up to two decimal places)

Given: Entropy change associated with heating orthorhombic sulphur from 0 K to 368.5K is 36.86 J K^-1.

Entropy change associated with cooling monoclinic sulphur from 368.5 K to 0 K is -37.8 J K^-1.

Askmemetallurgy Official

Asked: July 3, 2020In: Physical Metallurgy & Heat treatment

GATE MT 2017 Q34. For each of the following crystallographic system listed in column 1. Match the corresponding minimum symmetry in column 2.

Poll Results

8.7%(A) P-3,Q-4,R-2,S-1 ( 2 voters )

17.39%(B) P-4,Q-3,R-2,S-1 ( 4 voters )

8.7%(C) P-1,Q-2,R-4,S-3 ( 2 voters )

65.22%(D) P-4,Q-3,R-1,S-2 ( 15 voters )

Based On 23 Votes

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GATE MT 2017 Q34. For each of the following crystallographic system listed in column 1. Match the corresponding minimum symmetry in column 2.

Askmemetallurgy Official

Asked: July 3, 2020In: Mineral Processing & Non-ferrous Metallurgy

GATE MT 2017 Q33.

A zinc electrowinning cell is being operated at a current of 400 A, voltage of 3.5V, and a cathodic current efficiency of 90%, the specific energy consumption (in kg KJ-1 zinc) is _____. (answer up to two decimal places) Given Atomic ...Read more

A zinc electrowinning cell is being operated at a current of 400 A, voltage of 3.5V, and a cathodic current efficiency of 90%, the specific energy consumption (in kg KJ^-1 zinc) is _____. (answer up to two decimal places)

Given Atomic weight of zinc =65

Askmemetallurgy Official

Asked: July 3, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q32. Pure metals A and B form two real binary solid solutions α and β at a temperature T and pressure P. The free energy versus composition plots for both the solutions are given below. The condition for chemical equilibrium is:

Poll Results

11.11%(A) Mole fraction of A in α=mole fraction of A in βand mole fraction of B in α= mole fraction of B in β ( 2 voters )

5.56%(B) Mole fraction of B in α= mole fraction of A in β and mole fraction of A in α = mole fraction of B in β ( 1 voter )

66.67%(C) Activity of A in α= activity of A in β and activity of B in α=activity of B in β ( 12 voters )

16.67%(D) Activity of A in α= activity of B in β and activity of B in α= activity of A in β ( 3 voters )

Based On 18 Votes

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GATE MT 2017 Q32. Pure metals A and B form two real binary solid solutions α and β at a temperature T and pressure P. The free energy versus composition plots for both the solutions are given below. The condition for chemical equilibrium is:

Askmemetallurgy Official

Asked: July 3, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q31.

A solution contains 10-3 M of Fe+3 at 25°C. The solubility of product of Fe(OH)3 is 10-39. Assuming activity equals concentration, the maximum pH at which Fe+3 will precipitate as Fe(OH)3 is _______. (answer up to two decimal places)

A solution contains 10^-3 M of Fe⁺³ at 25°C. The solubility of product of Fe(OH)₃is 10^-39. Assuming activity equals concentration, the maximum pH at which Fe⁺³will precipitate as Fe(OH)₃is _______. (answer up to two decimal places)

Askmemetallurgy Official

Asked: July 2, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q30.

A stoichiometric equation of CO and pure oxygen at 1atm and 25°C flows into a combustion reactor. The molar flow rate of CO entering the reactor is 1kg-mol.h-1. The adiabatic flame temperature (in K) for the combustion of CO with ...Read more

A stoichiometric equation of CO and pure oxygen at 1atm and 25°C flows into a combustion reactor. The molar flow rate of CO entering the reactor is 1kg-mol.h-1. The adiabatic flame temperature (in K) for the combustion of CO with stoichiometric oxygen is ______. (answer up to two decimal places).
Given ΔH0298 (CO-CO2) =-282000 KJ (kg-mol-CO)-1, Cp(CO2)= 44 KJ (kg-mol K)-1

Askmemetallurgy Official

Asked: July 2, 2020In: Iron & Steel Making

GATE MT 2017 Q29.

In primary steel making, dissolved Oxygen (O) reacts with carbon (c ) to produce CO(g), at 1 atm pressure according to the reaction C+ O= CO. The equilibrium constant for this reaction is logK=1160/T + 2.003 , where T ...Read more

In primary steel making, dissolved Oxygen (O) reacts with carbon (c ) to produce CO(g), at 1 atm pressure according to the reaction C+ O= CO. The equilibrium constant for this reaction is logK=1160/T + 2.003 , where T is kelvin. Assuming the Henrian activity coefficient of both O and C to be unity, the dissolved oxygen content (in wt%) of a plain carbon steel melt with 0.7% C at 1600°C is _____(answer up to four decimal places)

Askmemetallurgy Official

Asked: July 2, 2020In: Iron & Steel Making

GATE MT 2017 28. A ladle containing molten steel is being discharged. The relevant forces are listed in column 1. Match them with their corresponding expressions in column 2. µ=viscosity, U= characteristic velocity, L= characteristic length, g=acceleration due to gravity, P=pressure.

Poll Results

85%(A) P-4,Q-3,R-2, S-1 ( 17 voters )

10%(B) P-1, Q-3, R-2, S-4 ( 2 voters )

5%(C) P-2,Q-3,R-4,S-1 ( 1 voter )

0%(D) P-4,Q-3,R-1,S-2

Based On 20 Votes

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GATE MT 2017 28. A ladle containing molten steel is being discharged. The relevant forces are listed in column 1. Match them with their corresponding expressions in column 2. µ=viscosity, U= characteristic velocity, L= characteristic length, g=acceleration due to gravity, P=pressure.

Askmemetallurgy Official

Asked: July 2, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q27.

CaCo3(s) dissociates in a closed system according to the reaction : CaCO3(s) = CaO(s) + CO2(g) Assuming the reaction is in thermal equilibrium, the degree(s) of freedom, F = _____.

CaCo₃(s) dissociates in a closed system according to the reaction :

CaCO₃(s) = CaO(s) + CO₂(g)

Assuming the reaction is in thermal equilibrium, the degree(s) of freedom, F = _____.

Askmemetallurgy Official

Asked: July 2, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 Q26. The pourbaix plot of reaction Al3+ + 2H2O = AlO2- + 4H+ in potential( E) versus pH diagram is :

Poll Results

11.11%A ( 5 voters )

8.89%B ( 4 voters )

66.67%C ( 30 voters )

13.33%D ( 6 voters )

Based On 45 Votes

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GATE MT 2017 Q26. The pourbaix plot of reaction Al3+ + 2H2O = AlO2- + 4H+ in potential( E) versus pH diagram is :

Askmemetallurgy Official

Asked: July 1, 2020In: Iron & Steel Making

GATE MT 2017 Q25.

During the end blow period in LD steelmaking, the de-carburisation rate is expressed by the equation : dc/dt= -(c-c*) are the instantaneous and equilibrium concentration of carbon in steel respectively, in units of wt%. Given that c*= 0.04 wt % ...Read more

During the end blow period in LD steelmaking, the de-carburisation rate is expressed by the equation : dc/dt= -(c-c*) are the instantaneous and equilibrium concentration of carbon in steel respectively, in units of wt%. Given that c*= 0.04 wt % and c(t=0 min) =0.4 wt%, the concentration of carbon in steel (in wt%) at t=1 min is ______ (answer up to three decimal places)

Askmemetallurgy Official

Asked: July 1, 2020In: Thermodynamics & Rate Processes

GATE MT 2017 24.

A continuous cast steel slab, 1m × 1m × 0.1m at 1298 K cools in air. The initial rate of heat loss (in kW) from the top surface of slab by radiation and convection is _____ (answer up to two ...Read more

A continuous cast steel slab, 1m × 1m × 0.1m at 1298 K cools in air. The initial rate of heat loss (in kW) from the top surface of slab by radiation and convection is _____ (answer up to two decimal places)

(Given (i) Ambient temperature= 298K (ii) emissivity of steel=0.8 (iii) convective heat transfer coefficient = 4.6 W m^-2K^-1(iv) Stefan-Boltzmann constant (σ)= 5.7 × 10⁸W m^-2K^-4

Askmemetallurgy Official

Asked: July 1, 2020In: DT & NDT

GATE MT 2017 Q23. Dye penetrant test is based on the principle of:

Poll Results

4.04%A. Polarised sound waves in liquid ( 4 voters )

2.02%B. Magnetic domain ( 2 voters )

5.05%C. Absorption of X-rays ( 5 voters )

88.89%D. Capillary action ( 88 voters )

Based On 99 Votes

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