Given the stress tensor, the maximum shear stress is MPa (round off to the nearest integer).

Given the stress tensor, the maximum shear stress is MPa (round off to the nearest integer).

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Home/GATE MT Mechanical metallurgy

Given the stress tensor, the maximum shear stress is MPa (round off to the nearest integer).

Given the stress tensor, the maximum shear stress is MPa (round off to the nearest integer).

Read lessHigh cycle fatigue data for an alloy at various alternating stresses, 𝜎a (see figure) is given below. A specimen of this alloy is subjected to multiple stress cycles sequentially in the following order: (i) first 5000 cycles at σa = ...Read more

High cycle fatigue data for an alloy at various alternating stresses, 𝜎_{a} (see figure) is given below.

A specimen of this alloy is subjected to multiple stress cycles sequentially in the following order: (i) first 5000 cycles at σa = 400 MPa followed by (ii) 25000 cycles at σa = 300 MPa and finally (iii) at σa = 500 MPa. Assuming that Miner’s law is obeyed, the number of cycles to failure at the final applied stress of

500 MPa is .

Read lessConsider a tilt boundary of misorientation of 2o in an aluminium grain. The lattice parameter of aluminium is 0.143 nm. The spacing between the dislocations that form the tilt boundary is ______ nm (round off to 2 decimal places).

Consider a tilt boundary of misorientation of 2^{o} in an aluminium grain. The lattice parameter of aluminium is 0.143 nm. The spacing between the dislocations that form the tilt boundary is ______ nm (round off to 2 decimal places).

From high temperature tensile testing, the flow stress (measured at the same value of strain) of an alloy was found to be 50 MPa at a strain rate of 0.1 s–1 and 70 MPa at a strain rate of 10 ...Read more

From high temperature tensile testing, the flow stress (measured at the same value of strain) of an alloy was found to be 50 MPa at a strain rate of 0.1 s^{–1} and 70 MPa at a strain rate of 10 s^{–1}. The strain rate sensitivity parameter is (round off to 3 decimal places).

Find the correct match between dislocation reactions (Column A) to the descriptions (Column B)

Find the correct match between dislocation reactions (**Column A**) to the descriptions (**Column B**)

12.5% (A) 𝜖̇ ∝ 𝑣2 ( 2 voters )

43.75% (B) 𝜖̇ ∝ 𝑣 ( 7 voters )

31.25% (C) 𝜖̇ ∝ 𝜌2 ( 5 voters )

12.5% (D) 𝜖̇ ∝ 𝜌 ( 2 voters )

Based On 16 Votes

30.95%(A) 𝑑𝜎/𝑑𝜖 = 0 ( 13 voters )

19.05% (B) 𝑑𝜎/ 𝑑𝜖 = ϵ ( 8 voters )

47.62% (C) 𝑑𝜎 / 𝑑𝜖 = σ ( 20 voters )

2.38% (D) 𝑑𝜎 / 𝑑𝜖 = ∞ ( 1 voter )

Based On 42 Votes

56.9%(A) [1̅01](111) ( 33 voters )

27.59%(B) [1̅10](111) ( 16 voters )

10.34%(C) [101](111̅) ( 6 voters )

5.17%(D) [011](111̅) ( 3 voters )

Based On 58 Votes

68.18%(A) The minimum creep rate is obtained in the primary stage (stage I). ( 45 voters )

15.15%(B) Creep resistance decreases with decrease in grain size. ( 10 voters )

4.55%(C) Coble creep occurs via grain boundary diffusion. ( 3 voters )

12.12%(D) Nabarro-Herring creep occurs via lattice diffusion. ( 8 voters )

Based On 66 Votes

A perfectly elastic-plastic material has a yield stress of 450 MPa and fractures at a strain 0f 0.45. The ratio of resilience to toughness for this material is _____ (answer up to three decimal places) Given the young’s modulus E=4.5 GPa

A perfectly elastic-plastic material has a yield stress of 450 MPa and fractures at a strain 0f 0.45. The ratio of resilience to toughness for this material is _____ (answer up to three decimal places)

Given the young’s modulus E=4.5 GPa

Read lessA steel component is subjected to fatigue loading : σ(maximum)= 200 MPa, σ(minimum)=0. The component has an initial crack length of 1mm. Propagation of crack is governed by: da/dN= 10-12 (ΔK)3, where, the crack length a is in metres, N ...Read more

A steel component is subjected to fatigue loading : σ(maximum)= 200 MPa, σ(minimum)=0. The component has an initial crack length of 1mm. Propagation of crack is governed by: da/dN= 10^{-12 }(ΔK)^{3}, where, the crack length a is in metres, N is the number of cycles and ΔK is in MPa m^{1/3}. The crack length of (in m) after one million cycles will be _____ (answer up to three decimal places)

A material which shows power law behaviour σ- = 50 Ē0.3, is being wire drawn. The maximum strain per pass in annealed condition (assume ideal work and efficiency ƞ=1) is _____. (answer up to two decimal places)

A material which shows power law behaviour σ- = 50 Ē^{0.3}, is being wire drawn. The maximum strain per pass in annealed condition (assume ideal work and efficiency ƞ=1) is _____. (answer up to two decimal places)

A rod is elastically deformed by a uniaxial stress resulting in a strain of 0.02. If the Poisson’s ratio is 0.3, the volumetric strain is ____ .(answer up to three decimal places)

A rod is elastically deformed by a uniaxial stress resulting in a strain of 0.02. If the Poisson’s ratio is 0.3, the volumetric strain is ____ .(answer up to three decimal places)

Read lessA brittle material (young’s modulus= 60 GPa and surface energy =0.5 Jm-2 ) has a surface crack of length 2 µm. the fracture strength (in MPa) of this material is _______ (answer up to two decimal places)

A brittle material (young’s modulus= 60 GPa and surface energy =0.5 Jm^{-2} ) has a surface crack of length 2 µm. the fracture strength (in MPa) of this material is _______ (answer up to two decimal places)

75%A. Gb/L ( 42 voters )

16.07%B. Gb^2/L ( 9 voters )

7.14%C. Gb^2/L^2 ( 4 voters )

1.79%D. Gb^2/2L^2 ( 1 voter )

Based On 56 Votes

21.01%A. Increase in the grain size ( 29 voters )

26.09%B. Decrease in the grain size ( 36 voters )

44.2%C. Addition of dispersoids ( 61 voters )

8.7%D. Annealing ( 12 voters )

Based On 138 Votes

76.47%A. Twinning and dislocation- slip ( 26 voters )

11.76%B.Dislocation-climb and dislocation- slip ( 4 voters )

11.76%C. Dislocation-slip and diffusion ( 4 voters )

0%D. Viscous flow and dislocation-slip ( 0 voters )

Based On 34 Votes

A single crystal of aluminium is subjected to 10 MPa tensile stress along the [321] crystallographic direction. The resolved shear stress on the (111̅) [101] slip system is ________(in MPa to two decimal places).

A single crystal of aluminium is subjected to 10 MPa tensile stress along the [321] crystallographic direction. The resolved shear stress on the (111̅) [101] slip system is ________(in MPa *to two decimal places)*.

Consider the following stress state imposed on a material: 90 50 0 𝜎 = [50 −20 0 MPa. 0 0 14] If the material ...Read more

Consider the following stress state imposed on a material:

90 50 0

𝜎 = [50 −20 0 MPa.

0 0 14]

If the material responds elastically with a volumetric strain 𝛥 = 3.5 × 10^{−4}, what is its bulk modulus?

(A) 150 GPa (B) 350 GPa

(C) 200 GPa (D) 400 GPa

Read less
25.81%(A)Both [A] and [R] are true and [R] is the correct reason for [A] ( 8 voters )

61.29%(B)Both [A] and [R] are true, but [R] is not the correct reason for [A] ( 19 voters )

6.45%(C)Both [A] and [R] are false ( 2 voters )

6.45%(D)[A] is true but [R] is false ( 2 voters )

Based On 31 Votes