BARC-15: What is the maximum number of phases that can co-exist in a Binary Phase Diagram?
BARC-15: What is the maximum number of phases that can co-exist in a Binary Phase Diagram?
Share
Connect with:
or use
Have an account? Sign In Now
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
It is based of the phase diagram we have taken if the phase diagram is drawn at atmospheric pressure then DOF= C-P+1 Then answer is 3 If we consider the diagram is not drawn at atmospheric pressure then DOF=C-P+2 Then answer is 4 Basically we take pressure constant for most of the cases for oRead more
It is based of the phase diagram we have taken if the phase diagram is drawn at atmospheric pressure then
DOF= C-P+1
Then answer is 3
If we consider the diagram is not drawn at atmospheric pressure then
DOF=C-P+2
Then answer is 4
Basically we take pressure constant for most of the cases for our convenience .
See lessIt is based on the Gibb's phase rule which is used for the determination of no of phases, compnents and the no of independent variables present in a phase diagram. F=C-P+2 where F=degree of freedom , C= no of components, P= no of phases and 2 is for temp and pressure. Generally binary phase diagramRead more
It is based on the Gibb’s phase rule which is used for the determination of no of phases, compnents and the no of independent variables present in a phase diagram.
F=C-P+2 where F=degree of freedom , C= no of components, P= no of phases and 2 is for temp and pressure. Generally binary phase diagram is considered with one atmospheric pressure. So here pressure is constant. So Gibb’s phase rule for a binary phase diagram is
F= C-P+1 .In a binary phase diagram components are 2.And to know the max no of phases the degree of freedom should be minimum,which is 0.
F=C-P+1 hence P=C-F+1. P=2-0+1=3 hence max no of phases are 3.
See lessThree, we can get it from the Gibbs phase rule.
Three, we can get it from the Gibbs phase rule.
See lessMax number of phases that can co exist in binary diagram is three. Max number of phases co exist, when degree of freedom is zero. (F=0). According to Gibb's phase rule F= C-P+1. For binary diagram C=2. If we apply these condition we get P=3.
Max number of phases that can co exist in binary diagram is three.
Max number of phases co exist, when degree of freedom is zero. (F=0). According to Gibb’s phase rule F= C-P+1. For binary diagram C=2. If we apply these condition we get P=3.
See lessGibbs phase rule : DOF = C - P + 2. For maximum phase, DOF should be zero. (negative is not possible) . So that, maximum number of phases co exist in binary system is four(4). DOF = 0; C = 2; -) P = 2 + 2 - 0 = 4.
Gibbs phase rule : DOF = C – P + 2. For maximum phase, DOF should be zero. (negative is not possible) . So that, maximum number of phases co exist in binary system is four(4).
DOF = 0; C = 2; -) P = 2 + 2 – 0 = 4.
See lessThe maximum no.of phases in a binary phase diagram are 3. By the degrees of freedom: F= C-P+1 F= 2-P+1 F=3-P ( Therefore, the maximum phases can be 3, if it is more than 3 the DOF is negative but it can never happen)
The maximum no.of phases in a binary phase diagram are 3.
By the degrees of freedom:
F= C-P+1
F= 2-P+1
F=3-P ( Therefore, the maximum phases can be 3, if it is more than 3 the DOF is negative but it can never happen)
See less4
- 4
See lessFour, liquid two solids, one coagulated intermediate phase, in an eutectic
Four, liquid two solids, one coagulated intermediate phase, in an eutectic
See less