FeO+nCO=Fe+(n-1)CO+CO2. How? Justify your answer why outgoing gases carry sufficient amount of CO from offtakes in b/f.
FeO+nCO=Fe+(n-1)CO+CO2. How? Justify your answer why outgoing gases carry sufficient amount of CO from offtakes in b/f.
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solve this eq using thermodynamics at TRZ temp(850c) finally you will get CO utilisation factor around nco = CO2 /(CO+Co2) = 0.3 This means if you use 100% CO gas only 30% CO is utilised to reduce feO and when the furnace atmosphere reaches around 70%CO there won't be further reduction. So, to reducRead more
solve this eq using thermodynamics at TRZ temp(850c) finally you will get CO utilisation factor around
nco = CO2 /(CO+Co2) = 0.3
This means if you use 100% CO gas only 30% CO is utilised to reduce feO and when the furnace atmosphere reaches around 70%CO there won’t be further reduction.
So, to reduce 1 mole of feO will require 3.3 moles of CO but only 1 mole of CO will be utilized.
feO + 3.3CO = fe + 2.3CO + CO2
In this reaction, wastage of 70% CO. Above TRZ zone this CO gas is utilized to covert hemetite to wustite and to facilitate this reaction min 20% CO atmosphere required in B. F.
That’s why, to meet the required thermodynamic condition in reaction steps in B. F. Outgoing gases contains Sufficient amount of CO while coming from off takes.
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See lessBlast furnace carries Nitrogen, its sensible heat will be utilized for Fe2O3- Fe3O4-FeO-Fe topochemical model reduction. But CO is also available from solution loss conversion. C+1/2(O2)=CO ie n/2 mole of CO formed; 0.21 mole of CO2 & 0.79 mole of N2. Total no. of moles=n/2+1. Mole fraction of CRead more
Blast furnace carries Nitrogen, its sensible heat will be utilized for Fe2O3- Fe3O4-FeO-Fe topochemical model reduction. But CO is also available from solution loss conversion. C+1/2(O2)=CO ie n/2 mole of CO formed; 0.21 mole of CO2 & 0.79 mole of N2. Total no. of moles=n/2+1. Mole fraction of CO = n/2×(1/[n/2+1]=(n/n+2), by taking n=1, %CO=33.3 and b/f off takes will carry 33.3%CO always. This answer will be edited later.
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