The driving force for sintering a compact consisting of spherical particles of radius R1 is delG1. if the particle size is reduced to R2 =0.1 R1, the corresponding driving force delG2=α delG; , where α is ______.
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answer is 10
answer is 10
See lessCould u help me with detailed solution.
Could u help me with detailed solution.
See lessIt'll be very much helpful if you could provide the solution to this problem.
It’ll be very much helpful if you could provide the solution to this problem.
See lessMy ans: 100 Driving force for sintering is inversely proportional to the surface area [∆G proportional to 1/(R^2)]. (∆G1)÷(∆G2)=(R2÷R1)^2 ∆G2=100∆G1 Corrections are welcomed and thanked.
My ans: 100
Driving force for sintering is inversely proportional to the surface area [∆G proportional to 1/(R^2)]. (∆G1)÷(∆G2)=(R2÷R1)^2
∆G2=100∆G1
Corrections are welcomed and thanked.
See lessThis queston is from gate mt 2015 paper ,and everywhere answer given is 10.
This queston is from gate mt 2015 paper ,and everywhere answer given is 10.
See lessHello Nitish Ji, Please refer to our latest answer. You can also find the notes & the problem solved in the Study material...Link for which is in this answer. https://askmemetallurgy.com/question/from-where-can-i-cover-the-powder-metallurgy-portion-of-gate-can-anyone-suggest-any-material/
Hello Nitish Ji,
Please refer to our latest answer. You can also find the notes & the problem solved in the Study material…Link for which is in this answer.
See lessAns is 10.
Ans is 10.
See less