### Poll Results

16.67%(A) the molar weight of an oxide divided by the molar weight of the metal consumed in oxide formation. ( 8 voters )

56.25%(B) the volume of the oxide divided by the volume of the metal consumed in oxide formation. ( 27 voters )

18.75%(C) the density of the oxide divided by the density of the metal consumed in oxide formation. ( 9 voters )

8.33%(D) the molar Gibbs energy of the oxide divided by the Gibbs energy of the metal consumed in oxide formation. ( 4 voters )

Based On 48 Votes

Correct answer is option B. The Pilling–Bedworth ratio (P–B ratio), in corrosion of metals, is the ratio of the volume of the elementary cell of a metal oxide to the volume of the elementary cell of the corresponding metal (from which the oxide is created). RPB= Voxide/ Vmetal

Correct answer is option B.

The Pilling–Bedworth ratio (P–B ratio), in corrosion of metals, is the ratio of the volume of the elementary cell of a metal oxide to the volume of the elementary cell of the corresponding metal (from which the oxide is created).

R

_{PB}= V_{oxide}/ V_{metal}