The Burger’s vector of a dislocation in a cubic crystal (with lattice parameter a) is a/2 [110]and dislocation line is along [112] direction. The angle (in degrees) between the dislocation line and its Burger’s vector is .
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The Burger’s vector of a dislocation in a cubic crystal (with lattice parameter a) is a/2 [110]and dislocation line is along [112] direction. The angle (in degrees) between the dislocation line and its Burger’s vector is .
Correct answer is in the range of 54-55. We know that, cosθ= (h1h2+k1k2+l1l2)/ √(h21+h12 +h12)√(h22+h22 +h22) On substitution, cos θ=( 1×1+1×1+2×0)/√(12+12+02)√(12+12+22) cos θ= 2/(√2×√6) cos θ= 54.735°
Correct answer is in the range of 54-55.
We know that, cosθ= (h1h2+k1k2+l1l2)/ √(h21+h12 +h12)√(h22+h22 +h22)
On substitution, cos θ=( 1×1+1×1+2×0)/√(12+12+02)√(12+12+22)
cos θ= 2/(√2×√6)
cos θ= 54.735°
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