A perfectly elastic-plastic material has a yield stress of 450 MPa and fractures at a strain 0f 0.45. The ratio of resilience to toughness for this material is _____ (answer up to three decimal places)
Given the young’s modulus E=4.5 GPa
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0.125 Resilience is the strain energy up to the elastic limit, where Toughness is energy observed per unit volume till fracture
0.125
See lessResilience is the strain energy up to the elastic limit, where Toughness is energy observed per unit volume till fracture
Correct answer is 0.125 Given that, σ=450×106 MPa and E= 4.5 ×109 MPa Engineering strain in elastic limit= σ/E= 450×106 / 4.5 ×109 = 0.1 Plastic strain= 0.45- 0.1= 0.35 Resilience/toughness= Area of region of A/(Area of region of A+ Area of region of B) = 1/2×0.1×450×106 /( 1/2(0.1×450×106 + 0.35×4Read more
Correct answer is 0.125
Given that, σ=450×106 MPa and E= 4.5 ×109 MPa
Engineering strain in elastic limit= σ/E= 450×106 / 4.5 ×109 = 0.1
Plastic strain= 0.45- 0.1= 0.35
Resilience/toughness= Area of region of A/(Area of region of A+ Area of region of B)
= 1/2×0.1×450×106 /( 1/2(0.1×450×106 + 0.35×450×106 )
=0.125
0.125
0.125
See less0.1249