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Pure iron transforms from body centered cubic (BCC) to face centered cubic (FCC) crystal structure at 912 °C. If the lattice parameter of the BCC phase is 0.293 nm and that of the FCC phase is 0.363 nm, the associated volume change is ______ (in % to one decimal place).
Lattice parameter of BCC = aBCC = 0.293 nm Lattice parameter of FCC = aFCC = 0.363 nm No. Of atoms per unit cell in BCC is 2 and that of FCC is 4 So percentage change = (aFCC3 /4 - aBCC3 /2)/ aBCC3 /2 ×100 = -4.92%
Lattice parameter of BCC = aBCC = 0.293 nm
Lattice parameter of FCC = aFCC = 0.363 nm
No. Of atoms per unit cell in BCC is 2 and that of FCC is 4
So percentage change =
(aFCC3 /4 – aBCC3 /2)/ aBCC3 /2 ×100 = -4.92%
See lessCorrect answer is (-4.98%). @Arpita Samal described it best. Thank you.
Correct answer is (-4.98%). Arpita Samal described it best. Thank you.
See less