At a temperature of 710 K, the vapour pressure of pure liquid Zn is given by: πππ(ππ§π = 1.0) = 3.6 Γ 10β4atm. The Raoultian activity coefficient (πΎππ) of Zn in Zn-Cd alloy liquid at 710 K is approximated by: ln(πΎππ) = 0.875(1 β πππ)2 . The ratio [ πππ(ππ§π=0.7) ] / πππ(ππ§π=1.0)for a liquid alloy with π= 0.7 is ________. (to two decimal places).
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See lessCorrect answer is 0.757 @Digbijaya igit described it best. Thank you.
Correct answer is 0.757 digbijaya igit igit described it best. Thank you.
See lessfirst calculate πΎππ Pzn = πΎππ(mole fraction of zn i.e 0.7) * Partial pressure at standard state (p=πΎππ *X zn*P0) then partial pressure cancels on both numerator and denominator.
first calculate πΎππ
Pzn = πΎππ(mole fraction of zn i.e 0.7) * Partial pressure at standard state
(p=πΎππ *X zn*P0)
then partial pressure cancels on both numerator and denominator.
See less0.757
0.757
See less