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Asked: June 7, 20202020-06-07T08:24:03+05:30 2020-06-07T08:24:03+05:30In: Thermodynamics & Rate Processes

GATE MT 2019 Q2. The variation of standard free energies for two oxides AO and BO with temperature are given below. The correct statement with reference to above figure is :

Poll Results

10.59%AO is a gas ( 9 voters )
56.47%BO is a gas ( 48 voters )
10.59%A will reduce BO above temperture T1 ( 9 voters )
22.35%B will reduce AO below temperature T1 ( 19 voters )
Based On 85 Votes

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GATE MT 2019 Q2. The variation of standard free energies for two oxides AO and BO with temperature are given below. The correct statement with reference to above figure is :
GATE MT 2019 Q2. The variation of standard free energies for two oxides AO and BO with temperature are given below. The correct statement with reference to above figure is :
GATE MT 2019 Question Paper With SolutionGATE MT Previous Year Questions With SolutionGATE MT Thermodynamicsstandard free energiesthermodynamics
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    1. digbijaya igit Platinum GATE 2021 QUALIFIED
      2020-06-07T17:04:22+05:30Added an answer on June 7, 2020 at 5:04 pm

      A will reduce BO below T1 and B will reduce AO above T1 . At higher temperature gases have lower free energy, hence BO should be gas.

      A will reduce BO below T1 and B will reduce AO above T1 . At higher temperature gases have lower free energy, hence BO should be gas.

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    2. Arpita Samal Platinum Metallurgical and Materials Engineering student
      2020-06-07T09:01:41+05:30Added an answer on June 7, 2020 at 9:01 am

      With reference to Ellingham diagram and concept BO is a gas

      With reference to Ellingham diagram and concept BO is a gas

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    3. SAI CHARAN Silver Metallurgical Engineering student
      2020-06-07T22:18:05+05:30Added an answer on June 7, 2020 at 10:18 pm

      According to ellingham diagram option B is right

      According to ellingham diagram option B is right

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    4. Shetty Gold
      2020-06-08T00:40:00+05:30Added an answer on June 8, 2020 at 12:40 am

      Option B according to Ellingham diagram

      Option B according to Ellingham diagram

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    5. Best Answer
      Askmemetallurgy Official official account of Askmemetallurgy
      2020-06-08T13:10:16+05:30Added an answer on June 8, 2020 at 1:10 pm

      Correct answer is option B. The slope of the ellingham diagram is -(delta)S. And we know that, entropy is proportional to gaseous species. BO must be a gaseous species then only its slope will be negative.

      Correct answer is option B.

      The slope of the ellingham diagram is -(delta)S.
      And we know that, entropy is proportional to gaseous species. BO must be a gaseous species then only its slope will be negative.

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