GATE MT 2019 Q24. An arc welding is performed at 400 Amperes, 20 V at a transverse speed of 5 mm/s. If the heat transfer efficiency is 0.6, the energy input per unit length( in J/mm, rounded off to the nearest integer ) during the process is ___________.

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This answer was edited.The heat input in the arc welding is described by the equation shown in picture. The important point is the involvement of efficiency in the equation. This shows that not all the available energy is beneficially used to melt material, because heat is conducted through the workpiece, some lost by radRead more

The heat input in the arc welding is described by the equation shown in picture. The important point is the involvement of efficiency in the equation. This shows that not all the available energy is beneficially used to melt material, because heat is conducted through the workpiece, some lost by radiation, some by convection to surrounding.

The solution is as shown.

See lessCorrect answer is in the range of 955-965 J/mm. @Rohit.km described it best. Thank you. Some peripheral lines related to this topic: Hinput = ηVI/speed

Correct answer is in the range of 955-965 J/mm. [email protected].km described it best. Thank you.

Some peripheral lines related to this topic:_{input}= ηVI/speedEfficiency = (0.6×20*400)/5 = 960 J/mm

Efficiency = (0.6×20*400)/5 = 960 J/mm

See lessThis answer was edited.Heat input per unit length = n*v*i/speed= (0.6*20*400) /5 = 960j/mm

See less^{Heat input per unit length = n*v*i/speed= (0.6*20*400) /5 = 960j/mm}