Steady state radial heat conduction through a hollow, infinitely long zirconia cylinder is governed by the following ordinary differential equation:

Where, T is the temperature and r is the radial distance. The inner surface of the hollow cylinder is maintained at 1473 K and the outer surface at 973 K. The rate of heat loss per unit length through the outer surface of the hollow cylinder (in 𝑊. 𝑚−1, rounded off to the nearest integer) is __________.
Given: Inner radius of cylinder = 0.05 m; outer radius of cylinder = 0.07 m and thermal conductivity of zirconia (k) = 2 𝑊. 𝑚−1. 𝐾−1.

See lessCorrect answer is in the range of 18660-18690. @Digbijaya igit described it best. Thank you.
Correct answer is in the range of 18660-18690. digbijaya igit igit described it best. Thank you.
See less