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Asked: 2020-06-15T17:00:00+05:30 In:

GATE MT 2019 Q42

The critical radius (in nm, rounded off to one decimal place) of nickel nucleus during solidification at 1673 K is    _______ .Given: Enthalpy of fusion of nickel = 2.65 × 109 𝐽. 𝑚-3; Liquid-solid interfacial energy = 0.5 𝐽. 𝑚-2, and Equilibrium melting temperature of nickel = 1728 K.

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    1. Best Answer
      Platinum GATE 2021 QUALIFIED
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    2. Platinum Metallurgical and Materials Engineering student

      Critical radius r* = -2y / delta Gv Where delta Gv (driving force)= (delta H * delta T)/ Tm Substituting the values we got Critical radius is 11.28 nm

      Critical radius r* = -2y / delta Gv

      Where delta Gv (driving force)= (delta H * delta T)/ Tm

      Substituting the values we got Critical radius is 11.28 nm

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    3. Platinum GATE Metallurgy Coaching

      Hi, For this problem you need to remember certain formulas or you can derive using energy balance equation. Here is solution given in this video at 10:24  https://www.youtube.com/watch?v=Kr4qL54E-zs&list=PLFS_xICJ_zVPwqvTZ6QToink9EOBilj-x&index=9

      Hi,

      For this problem you need to remember certain formulas or you can derive using energy balance equation.

      Here is solution given in this video at 10:24 

      https://www.youtube.com/watch?v=Kr4qL54E-zs&list=PLFS_xICJ_zVPwqvTZ6QToink9EOBilj-x&index=9

      See less
      • 3
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