GATE MT 2020 Q16. A component subjected to tensile stress in a mechanical device is monitored periodically for cracks by NDT. The NDT technique can only detect cracks (both surface and internal) which are larger than 1 mm. Keeping a 10 % margin of safety, the maximum allowed tensile stress on the component will be ______MPa. (Round off to the nearest integer). Given, fracture toughness K(Ic) =30MPa m(1/2) and assume crack geometry factor of unity.
GATE MT 2020 Q16. A component subjected to tensile stress in a mechanical device is monitored periodically for cracks by NDT. The NDT technique can only detect cracks (both surface and internal) which are larger than 1 mm. Keeping a 10 % margin of safety, the maximum allowed tensile stress on the component will be ______MPa. (Round off to the nearest integer). Given, fracture toughness K(Ic) =30MPa m(1/2) and assume crack geometry factor of unity.
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K = y * sigma * √πc Y =1 C = 1*10^-3 meters K = 30MPa Sigma = 535.23 MPa Safety margin = 10% So now sigma is 90% of 535.23MPa Sigma = 0.90*535.23= 481.7MPa
K = y * sigma * √πc
Y =1
C = 1*10^-3 meters
K = 30MPa
Sigma = 535.23 MPa
Safety margin = 10%
So now sigma is 90% of 535.23MPa
Sigma = 0.90*535.23= 481.7MPa
See lessCorrect answer is in the range of 480-490. @Digbijaya igit described it best. Thank you. Some peripheral lines related to this topic: NDT technique is used only to detect cracks( both internal and surface) Fracture toughness, 𝐾(𝐼𝐶)=𝜎√𝜋𝑐 where K(IC) is fracture toughness, sigma is tensile stress andRead more
Correct answer is in the range of 480-490. digbijaya igit igit described it best. Thank you.
Some peripheral lines related to this topic:
481.7MPa
481.7MPa
See less