Correct answer is 4 Kg/m^2 year. @Digbiyaya igit described it best. Thank you. Some peripheral lines related to this topic: Rate of corrosion = weight loss/(exposed area)×(time) Units are : Kg/m^2 year
Correct answer is 4 Kg/m^2 year. @Digbiyaya igit described it best. Thank you.
Some peripheral lines related to this topic:
Rate of corrosion = weight loss/(exposed area)×(time)
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Corrosion rate is 4 .
Corrosion rate is 4 .
See lessCorrect answer is 4 Kg/m^2 year. @Digbiyaya igit described it best. Thank you. Some peripheral lines related to this topic: Rate of corrosion = weight loss/(exposed area)×(time) Units are : Kg/m^2 year
Correct answer is 4 Kg/m^2 year. @Digbiyaya igit described it best. Thank you.
Some peripheral lines related to this topic:
See less4
4
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